发布网友 发布时间:2022-04-24 11:31
共3个回答
热心网友 时间:2023-10-11 06:44
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热心网友 时间:2023-10-11 06:45
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.
1/(x 1)(x 2)(x 3)=1/(x 1)[1/(x 2)-1/(x 3)]
=1/[(x 1)(x 2)]-1/[(x 1)(x 3)]
=1/(x 1)-1/(x 2)-1/2[1/(x 1)-1/(x 3)]
=1/[2(x 1)]-1/(x 2) 1/[2(x 3)]
∫x/(x a)dx=∫[1-a/(x a)]dx=x-aln|x a| C
求不定积分:
∫x/(x 1)(x 2)(x 3)dx
=∫x/[2(x 1)]-x/(x 2)-x/[2(x 3)]dx
=1/2∫x/(x 1)dx-∫x/(x 2)dx 1/2∫x/(x 3)dx
=1/2(x-ln|x 1|)-(x-2ln|x 2|) 1/2(x-3ln|x 3|) C
=-1/2ln|x 1| 2ln|x 2|-3/2ln|x 3| C
热心网友 时间:2023-10-11 06:45
注意细节
希望可以帮到你