已知函数f(x)=2√3sinxcosx+2cos^2x-1,
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发布时间：2024-10-23 16:44
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时间：2024-10-24 06:42
f(x)= 2√3sinxcosx+2cos^2x-1
=√3sin2x+cos2x
=2(√3/2*sin2x+1/2*cos2x)
=2(sin2xcosπ/3+cos2xsinπ/3)
=2sin(2x+π/3)
T=2π/2=π
当x=-π/6时 ,f(x)min= -2
当x=π/12时 ,f(x)max=2
