计算(3+1)(3^2+1(3^4+1)(3^8+1)(3^16+1)感谢必采纳
发布网友
发布时间：2024-10-24 15:00
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热心网友
时间：2024-11-05 23:30
(3 1/3)(3^2 1/3^2)（3^4 1/3^4)(3^8 1/3^8）(3^16 1/3^16
= (3-1/3) * (3 1/3)(3^2 1/3^2)（3^4 1/3^4)(3^8 1/3^8）(3^16 1/3^16) / (3-1/3)
= (3^2 - 1/3^2) (3^2 1/3^2)（3^4 1/3^4)(3^8 1/3^8）(3^16 1/3^16) / (3-1/3)
= (3^4 - 1/3^4)（3^4 1/3^4)(3^8 1/3^8）(3^16 1/3^16) / (3-1/3)
= (3^8 - 1/3^8 ) (3^8 1/3^8）(3^16 1/3^16) / (3-1/3)
= (3^16 - 1/3^16) (3^16 1/3^16) / (3-1/3)
= (3^32 - 1/3^32) / (3 - 1/3)
= (3^32 - 1/3^32) / (8/3)
= (3^33 - 1/3^31) / 8
